Two particles A and B are moving in uniform circular motion in concentric circles of radii ra and rb (with speed vA and vB respectively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be :

Question

Two particles A and B are moving in uniform circular motion in concentric circles of radii ra and rb (with speed vA and vB respectively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be : (A) rB: rA (B) 1:1 (C) rA: rB (D) vA: vB

Tardigrade Admin · Accepted Answer

TA = TB =T ωA = (2π/TA) ωB = (2π/TB) (ωA/ωB ) = (TB/TA) =(T/T) = 1

Q. Two particles A and B are moving in uniform circular motion in concentric circles of radii $r_{a}$ and $r_{b}$ (with speed $v_{A}$ and $v_{B}$ respectively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be :

$r_{B} : r_{A}$

1:1

$r_{A} : r_{B}$

$v_{A} : v_{B}$

$T_{A} = T_{B} = T$
$ω_{A} = \frac{2 π}{T _{A}}$
$ω_{B} = \frac{2 π}{T _{B}}$
$\frac{ω _{A}}{ω _{B}} = \frac{T _{B}}{T _{A}} = \frac{T}{T} = 1$

Q. Two particles A and B are moving in uniform circular motion in concentric circles of radii ra​ and rb​ (with speed vA​ and vB​ respectively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be :

rB​:rA​

1:1

rA​:rB​

vA​:vB​

TA​=TB​=T ωA​=TA​2π​ ωB​=TB​2π​ ωB​ωA​​=TA​TB​​=TT​=1

Q. Two particles A and B are moving in uniform circular motion in concentric circles of radii $r_{a}$ and $r_{b}$ (with speed $v_{A}$ and $v_{B}$ respectively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be :

$r_{B} : r_{A}$

$r_{A} : r_{B}$

$v_{A} : v_{B}$

$T_{A} = T_{B} = T$
$ω_{A} = \frac{2 π}{T _{A}}$
$ω_{B} = \frac{2 π}{T _{B}}$
$\frac{ω _{A}}{ω _{B}} = \frac{T _{B}}{T _{A}} = \frac{T}{T} = 1$