Two man of mass 50 kg and 60 kg on diametrically opposite point of a turntable of mass 90 kg . The turntable is free to rotate about vertical axis. The two men start moving towards each other along the circumference of table. The angle rotated by table when the two men meet each other -

Question

Two man of mass 50 kg and 60 kg on diametrically opposite point of a turntable of mass 90 kg . The turntable is free to rotate about vertical axis. The two men start moving towards each other along the circumference of table. The angle rotated by table when the two men meet each other - (A) 8.2°  (B) 4.5°  (C) 2.8°  (D) 6.8°

Tardigrade Admin · Accepted Answer

Let ‘θ ’ be angle rotated by turntable Let mass of man 1=m1 (= 50 k g) Let mass of man 2=m2 (= 60 k g) Let mass of turntable=m (= 90 k g) <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-uifkimpn3der.png" /> ∴ m 1(90°+θ)+ m 2 -(90°-θ) + m ⋅ θ=0 ⇒ θ=4.5°

Q. Two man of mass $50 k g$ and $60 k g$ on diametrically opposite point of a turntable of mass $90 k g$ . The turntable is free to rotate about vertical axis. The two men start moving towards each other along the circumference of table. The angle rotated by table when the two men meet each other -

$8. 2^{\circ}$

$4. 5^{\circ}$

$2. 8^{\circ}$

$6. 8^{\circ}$

Let $‘ θ ’$ be angle rotated by turntable
Let mass of man $1 = m_{1} (= 50 k g)$
Let mass of man $2 = m_{2} (= 60 k g)$
Let mass of $t u r n t ab l e = m (= 90 k g)$

$∴ m_{1} (9 0^{\circ} + θ) + m_{2} {- (9 0^{\circ} - θ)} + m \cdot θ = 0$
$\Rightarrow θ = 4. 5^{\circ}$

Q. Two man of mass 50kg and 60kg on diametrically opposite point of a turntable of mass 90kg . The turntable is free to rotate about vertical axis. The two men start moving towards each other along the circumference of table. The angle rotated by table when the two men meet each other -

8.2∘

4.5∘

2.8∘

6.8∘