Two long parallel current carrying conductors 30 cm apart having current each of 10 A in same direction, then value of magnetic field at a point of 15 cm between them, from any of the wire.

Question

Two long parallel current carrying conductors 30 cm apart having current each of 10 A in same direction, then value of magnetic field at a point of 15 cm between them, from any of the wire. (A) Zero (B) 6 × 10-5 T (C) 1.5 × 10-5 T (D) 3 × 10-5 T

Tardigrade Admin · Accepted Answer

| vecB1|=| vecB2| <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/1cb0b06fd6d0f468cf8a03a0ab529ccd-.png" /> Also vec B 1 is into the plane and vec B 2 is out of the plane. ⇒ vec B text net = text zero

Q. Two long parallel current carrying conductors $30 c m$ apart having current each of $10 A$ in same direction, then value of magnetic field at a point of $15 c m$ between them, from any of the wire.

Zero

$6 \times 1 0^{- 5} T$

$1.5 \times 1 0^{- 5} T$

$3 \times 1 0^{- 5} T$

$∣ ∣ B_{1} ∣ ∣ = ∣ ∣ B_{2} ∣ ∣$

Also $B_{1}$ is into the plane and $B_{2}$ is out of the plane.
$\Rightarrow B_{net} = zero$

Q. Two long parallel current carrying conductors 30cm apart having current each of 10A in same direction, then value of magnetic field at a point of 15cm between them, from any of the wire.

Zero

6×10−5T

1.5×10−5T

3×10−5T

∣∣​B1​∣∣​=∣∣​B2​∣∣​ Also B1​ is into the plane and B2​ is out of the plane. ⇒Bnet ​= zero

Q. Two long parallel current carrying conductors $30 c m$ apart having current each of $10 A$ in same direction, then value of magnetic field at a point of $15 c m$ between them, from any of the wire.

$6 \times 1 0^{- 5} T$

$1.5 \times 1 0^{- 5} T$

$3 \times 1 0^{- 5} T$

$∣ ∣ B_{1} ∣ ∣ = ∣ ∣ B_{2} ∣ ∣$

Also $B_{1}$ is into the plane and $B_{2}$ is out of the plane.
$\Rightarrow B_{net} = zero$