Two liquids A and B are at 32 oC and 24 oC. When mixed in equal masses, the temperature of mixture is found to be 28 oC. Their specific heats are in the ratio

Question

Two liquids A and B are at 32 oC and 24 oC. When mixed in equal masses, the temperature of mixture is found to be 28 oC. Their specific heats are in the ratio (A) 3:2 (B) 2:3 (C) 1:1 (D) 4:3

Tardigrade Admin · Accepted Answer

Let specific heats of liquids A and B are respectively

S_{A}

and

S_{B}

.
It is given that

T_{A} = 3 2^{o} C, T_{B} = 2 4^{o} C

and

T_{mi x} = 2 8^{o} C

When these liquids are mixed, then heat lost by

A =

heat gained by B

\Rightarrow m S_{A} Δ T = m S_{B} Δ T^{'}

\Rightarrow m S_{A} (T_{A} - T_{mi x}) = m S_{B} (T_{mi x} - T_{B})

\Rightarrow S_{A} (32 - 28) = S_{B} (28 - 24)

\Rightarrow S_{A} \times 4 = S_{B} \times 4

\Rightarrow S_{A} : S_{B} = 1 : 1

Q. Two liquids A and B are at $3 2^{o} C$ and $2 4^{o} C .$ When mixed in equal masses, the temperature of mixture is found to be $2 8^{o} C .$ Their specific heats are in the ratio

$3 : 2$

$2 : 3$

$1 : 1$

$4 : 3$

Q. Two liquids A and B are at 32oC and 24oC. When mixed in equal masses, the temperature of mixture is found to be 28oC. Their specific heats are in the ratio

3:2

2:3

1:1

4:3

Q. Two liquids A and B are at $3 2^{o} C$ and $2 4^{o} C .$ When mixed in equal masses, the temperature of mixture is found to be $2 8^{o} C .$ Their specific heats are in the ratio

$3 : 2$

$2 : 3$

$1 : 1$

$4 : 3$