Two identical strings X and Z made of same material have tension T X and T Z in them. It their fundamental frequencies are 450 Hz and 300 Hz , respectively, then the ratio T x / T 7, is :

Question

Two identical strings X and Z made of same material have tension T X and T Z in them. It their fundamental frequencies are 450 Hz and 300 Hz , respectively, then the ratio T x / T 7, is : (A) 0.44 (B) 1.5 (C) 2.25 (D) 1.25

Tardigrade Admin · Accepted Answer

f =(1/2 ℓ) √( T /μ) For identical string l and μ will be same f propto √ T (450/300)=√( T x / T y ) ( T x / T y )=(9/4)=2.25

Q. Two identical strings $X$ and $Z$ made of same material have tension $T_{X}$ and $T_{Z}$ in them. It their fundamental frequencies are $450 Hz$ and $300 Hz,$ respectively, then the ratio $T_{x} / T_{7}$ , is :

0.44

1.5

2.25

1.25

$f = \frac{1}{2 ℓ} \frac{T}{μ}$
For identical string $l$ and $μ$ will be same
$f \propto T$
$\frac{450}{300} = \frac{T _{x}}{T _{y}}$
$\frac{T _{x}}{T _{y}} = \frac{9}{4} = 2.25$

Q. Two identical strings X and Z made of same material have tension TX​ and TZ​ in them. It their fundamental frequencies are 450Hz and 300Hz, respectively, then the ratio Tx​/T7​, is :

0.44

1.5

2.25

1.25

f=2ℓ1​μT​​ For identical string l and μ will be same f∝T​ 300450​=Ty​Tx​​​ Ty​Tx​​=49​=2.25

Q. Two identical strings $X$ and $Z$ made of same material have tension $T_{X}$ and $T_{Z}$ in them. It their fundamental frequencies are $450 Hz$ and $300 Hz,$ respectively, then the ratio $T_{x} / T_{7}$ , is :

$f = \frac{1}{2 ℓ} \frac{T}{μ}$
For identical string $l$ and $μ$ will be same
$f \propto T$
$\frac{450}{300} = \frac{T _{x}}{T _{y}}$
$\frac{T _{x}}{T _{y}} = \frac{9}{4} = 2.25$