Two identical planets are orbiting around a star in elliptical paths having their semi-major axes in the ratio of 1:9. If life of man on 1s t planet is 80 years then what will be his life on 2n d planet in terms of that planet's year? (Approximate the answer to the nearest integer)

Question

Two identical planets are orbiting around a star in elliptical paths having their semi-major axes in the ratio of 1:9. If life of man on 1s t planet is 80 years then what will be his life on 2n d planet in terms of that planet's year? (Approximate the answer to the nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Life years =( text Total time to live / text One planet year ) n=(t/T) (n1/n2)=(T2/T1)=((9/1))3 / 2=27 n2=(n1/27)=(80/27)=2.96

Q. Two identical planets are orbiting around a star in elliptical paths having their semi-major axes in the ratio of 1:9. If life of man on 1st planet is 80 years then what will be his life on 2nd planet in terms of that planet's year? (Approximate the answer to the nearest integer)

Life years = One planet year Total time to live ​ n=Tt​ n2​n1​​=T1​T2​​=(19​)3/2=27 n2​=27n1​​=2780​=2.96

Life years $= \frac{Total time to live}{One planet year}$
$n = \frac{t}{T}$
$\frac{n _{1}}{n _{2}} = \frac{T _{2}}{T _{1}} = (\frac{9}{1})^{3/2} = 27$
$n_{2} = \frac{n _{1}}{27} = \frac{80}{27} = 2.96$