Two identical bar magnets are placed one above the other such that they are mutually perpendicular and bisect each other. The time period of this combination in a horizontal magnetic field is T. The time period of each magnet in the same field is

Question

Two identical bar magnets are placed one above the other such that they are mutually perpendicular and bisect each other. The time period of this combination in a horizontal magnetic field is T. The time period of each magnet in the same field is (A) √2 T (B) 2(1/4) T (C) 2-(1/4) T (D) 2-(1/2) T

Tardigrade Admin · Accepted Answer

Time period of combination, <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6537efb8f444bad73ea5dc06f0b1abd9-.png" /> T=2 π √(2 I/√2 M .H) ...(i) and time period of each magnet, T'=2 π √(T/M H) ...(ii) From (i) and (ii), we get T'=(T/21 / 4)=2-1 / 4 T

Q. Two identical bar magnets are placed one above the other such that they are mutually perpendicular and bisect each other. The time period of this combination in a horizontal magnetic field is $T$ . The time period of each magnet in the same field is

$2 T$

$2^{\frac{1}{4}} T$

$2^{- \frac{1}{4}} T$

$2^{- \frac{1}{2}} T$

Time period of combination,

$T = 2 π \frac{2 I}{2 M . H}$ ...(i)
and time period of each magnet,
$T^{'} = 2 π \frac{T}{M H}$ ...(ii)
From (i) and (ii), we get
$T^{'} = \frac{T}{2 ^{1/4}} = 2^{- 1/4} T$

Q. Two identical bar magnets are placed one above the other such that they are mutually perpendicular and bisect each other. The time period of this combination in a horizontal magnetic field is T. The time period of each magnet in the same field is

2​T

241​T

2−41​T

2−21​T