Two equal and opposite charges of 2× 1-10C are placed at a distance of 1 cm forming a dipole and are placed in a electric field of 2× 105N text/C . The maximum torque on dipole is :

Question

Two equal and opposite charges of 2× 1-10C are placed at a distance of 1 cm forming a dipole and are placed in a electric field of 2× 105N text/C . The maximum torque on dipole is : (A)  2√2× 10-6 textNm  (B)  8× 108 textNm  (C)  4× 10-7 textNm  (D)  4× 10-9 textNm

Tardigrade Admin · Accepted Answer

τ =p× E=pE sin θ τ max =p× E (As θ =90° , p=ql ) =ql× E=2× 10-10× 1× 10-2× 2× 105 =4× 10-7Nm

Q. Two equal and opposite charges of $2 \times 1^{- 10} C$ are placed at a distance of 1 cm forming a dipole and are placed in a electric field of $2 \times 10^{5} N / C$ . The maximum torque on dipole is :

$22 \times 10^{- 6} Nm$

$8 \times 10^{8} Nm$

$4 \times 10^{-}^{7} Nm$

$4 \times 10^{-}^{9} Nm$

$τ = p \times E = pE sin θ$ $τ_{m a x} = p \times E$ (As $θ = 90^{\circ},$ $p = ql$ ) $= ql \times E = 2 \times 10^{- 10} \times 1 \times 10^{- 2} \times 2 \times 10^{5}$ $= 4 \times 10^{- 7} N m$

Q. Two equal and opposite charges of 2×1−10C are placed at a distance of 1 cm forming a dipole and are placed in a electric field of 2×105N/C . The maximum torque on dipole is :

22​×10−6Nm

8×108Nm

4×10−7Nm

4×10−9Nm