Two dices are rolled. If both dices have six faces numbered 1,2,3,5,7 and 11 , then the probability that the sum of the numbers on the top faces is less than or equal to 8 is:

Question

Two dices are rolled. If both dices have six faces numbered 1,2,3,5,7 and 11 , then the probability that the sum of the numbers on the top faces is less than or equal to 8 is: (A) (4/9) (B) (17/36) (C) (5/12) (D) (1/2)

Tardigrade Admin · Accepted Answer

n ( E )=5+4+4+3+1=17 So, P ( E )=(17/36)

Q. Two dices are rolled. If both dices have six faces numbered $1, 2, 3, 5, 7$ and 11 , then the probability that the sum of the numbers on the top faces is less than or equal to 8 is:

$\frac{4}{9}$

$\frac{17}{36}$

$\frac{5}{12}$

$\frac{1}{2}$

$n (E) = 5 + 4 + 4 + 3 + 1 = 17$
So, $P (E) = \frac{17}{36}$

Q. Two dices are rolled. If both dices have six faces numbered 1,2,3,5,7 and 11 , then the probability that the sum of the numbers on the top faces is less than or equal to 8 is:

94​

3617​

125​

21​