Question

Two dice are thrown together. The probability of getting the sum $7$ is

• A. $\frac{7}{36}$
• B. $\frac{1}{36}$
• C. $\frac{1}{6}$
• D. None of these

Answer 1

Answer: (C)

Number of ways of getting the sum seven
{(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)}
$\therefore$ Required probability $=\frac{6}{36}=\frac{1}{6}$