Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I = I0 sin ω t, where I0= 10 A and ω= 100 π rad/sec. The maximum value ofe.m.f. in the second coil is

Question

Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I = I0 sin ω t, where I0= 10 A and ω= 100 π rad/sec. The maximum value ofe.m.f. in the second coil is (A) π (B) 5π (C) 2π (D) 4π

Tardigrade Admin · Accepted Answer

As |∈|=M(dI/dt)=M(d/dt)(I0sin ω t)=MI0ω cos ω t ∴ ∈max=0.005×10×100 π×1=5π.

Q. Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation $I = I_{0} s inω t,$ where $I_{0} = 10 A$ and $ω = 100 π$ rad/sec. The maximum value ofe.m.f. in the second coil is

$π$

$5 π$

$2 π$

$4 π$

As $∣ \in ∣ = M \frac{d I}{d t} = M \frac{d}{d t} (I_{0} s in ω t) = M I_{0} ω cos ω t$
$∴ \in_{ma x} = 0.005 \times 10 \times 100 π \times 1 = 5 π .$

Q. Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I=I0​sinωt, where I0​=10A and ω=100π rad/sec. The maximum value ofe.m.f. in the second coil is

π

5π

2π

4π

As ∣∈∣=MdtdI​=Mdtd​(I0​sinωt)=MI0​ωcosωt ∴∈max​=0.005×10×100π×1=5π.

Q. Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation $I = I_{0} s inω t,$ where $I_{0} = 10 A$ and $ω = 100 π$ rad/sec. The maximum value ofe.m.f. in the second coil is

$π$

$5 π$

$2 π$

$4 π$

As $∣ \in ∣ = M \frac{d I}{d t} = M \frac{d}{d t} (I_{0} s in ω t) = M I_{0} ω cos ω t$
$∴ \in_{ma x} = 0.005 \times 10 \times 100 π \times 1 = 5 π .$