Q.
Two charged particles having charge 1μC and −1μC and of mass 50g each are held at rest while their separation is 2m. Find the relative velocity of the particles when their separation is 0.5m.
1860
197
Electrostatic Potential and Capacitance
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Solution:
Speed of both will be same at any time, (KE+PE)f=(KE+PE)i 2(21mv2)−0.59×109×10−12 =−29×109×10−12+0 mv2=9×10−3[0.51−21]
Putting m=50/1000;v=1033m/s