Two charged capacitors have their outer plates fixed and inner plates connected by a spring of force constant ' k'. The charge on each capacitor is q. Find the extension in the spring at equilibrium

Question

Two charged capacitors have their outer plates fixed and inner plates connected by a spring of force constant ' k'. The charge on each capacitor is q. Find the extension in the spring at equilibrium (A) (q2/2 A ε0 k) (B) (q2/4 A ε0 k) (C) (q2/A ε0 k) (D) Zero

Tardigrade Admin · Accepted Answer

F=k x=(q2/2 A ε0) x=(q2/2 A ε0 k)

Q. Two charged capacitors have their outer plates fixed and inner plates connected by a spring of force constant ' $k$ '. The charge on each capacitor is $q$ . Find the extension in the spring at equilibrium

$\frac{q ^{2}}{2 A ε _{0} k}$

$\frac{q ^{2}}{4 A ε _{0} k}$

$\frac{q ^{2}}{A ε _{0} k}$

Zero

$F = k x = \frac{q ^{2}}{2 A ε _{0}}$
$x = \frac{q ^{2}}{2 A ε _{0} k}$

Q. Two charged capacitors have their outer plates fixed and inner plates connected by a spring of force constant ' k'. The charge on each capacitor is q. Find the extension in the spring at equilibrium

2Aε0​kq2​

4Aε0​kq2​

Aε0​kq2​