Two bodies of masses 10 kg and 100 kg are separated by a distance of 2 m . The gravitational potential at the mid-point of the line joining the two bodies is:

Question

Two bodies of masses 10 kg and 100 kg are separated by a distance of 2 m . The gravitational potential at the mid-point of the line joining the two bodies is: (A) -7.3× 10- 7 J / k g (B) -7.3× 10- 8 J / k g (C) -7.3× 10- 9 J / k g (D) -7.3× 10- 6 J / k g

Tardigrade Admin · Accepted Answer

As we know, gravitational potential V=(- G M/R) Gravitational potential at mid point, =-(G × 10/1)-(G × 100/1)=-110 G =- 110× 6.67× 10- 11 J k g- 1 =-7.3× 10- 9 text J textkg- 1

Q. Two bodies of masses $10 k g$ and $100 k g$ are separated by a distance of $2 m$ . The gravitational potential at the mid-point of the line joining the two bodies is:

$- 7.3 \times 1 0^{- 7} J / k g$

$- 7.3 \times 1 0^{- 8} J / k g$

$- 7.3 \times 1 0^{- 9} J / k g$

$- 7.3 \times 1 0^{- 6} J / k g$

As we know, gravitational potential
$V = \frac{- GM}{R}$
Gravitational potential at mid point,
$= - \frac{G \times 10}{1} - \frac{G \times 100}{1} = - 110 G$
$= - 110 \times 6.67 \times 1 0^{- 11} J k g^{- 1}$
$= - 7.3 \times 1 0^{- 9} J kg^{- 1}$

Q. Two bodies of masses 10kg and 100kg are separated by a distance of 2m . The gravitational potential at the mid-point of the line joining the two bodies is:

−7.3×10−7J/kg

−7.3×10−8J/kg

−7.3×10−9J/kg

−7.3×10−6J/kg