Two blocks of masses 3 m and m are connected by a massless and inextensible cord passing over a massless and frictionless pulley. Calculate the magnitude of acceleration of the centre of mass of the system when the blocks are allowed to accelerate. (g=10 ms -2)

Question

Two blocks of masses 3 m and m are connected by a massless and inextensible cord passing over a massless and frictionless pulley. Calculate the magnitude of acceleration of the centre of mass of the system when the blocks are allowed to accelerate. (g=10 ms -2) (A) 0.5 ms -2 (B) 1.5 ms -2 (C) 2.5 ms -2 (D) 3.5 ms -2

Tardigrade Admin · Accepted Answer

a=((m2-m1/m2+m1)) g Here m2=3 m, m1=m ⇒ a3 m=((3 m-m/3 m+m)) g=(g/2) downward am=(g/2) upward a cm =((3 m)(+(g/2))+(m)(-(g/2))/3 m+m)=(m g/4 m)=(g/4) downward =(10/4)=2.5 ms -2

Q. Two blocks of masses 3 m and m are connected by a massless and inextensible cord passing over a massless and frictionless pulley. Calculate the magnitude of acceleration of the centre of mass of the system when the blocks are allowed to accelerate. $(g = 10 m s^{- 2})$

$0.5 m s^{- 2}$

$1.5 m s^{- 2}$

$2.5 m s^{- 2}$

$3.5 m s^{- 2}$

Q. Two blocks of masses 3 m and m are connected by a massless and inextensible cord passing over a massless and frictionless pulley. Calculate the magnitude of acceleration of the centre of mass of the system when the blocks are allowed to accelerate. (g=10ms−2)

0.5ms−2

1.5ms−2

2.5ms−2

3.5ms−2

a=(m2​+m1​m2​−m1​​)g Here m2​=3m,m1​=m ⇒a3m​=(3m+m3m−m​)g=2g​ downward am​=2g​ upward acm​=3m+m(3m)(+2g​)+(m)(−2g​)​=4mmg​=4g​ downward =410​=2.5ms−2

Q. Two blocks of masses 3 m and m are connected by a massless and inextensible cord passing over a massless and frictionless pulley. Calculate the magnitude of acceleration of the centre of mass of the system when the blocks are allowed to accelerate. $(g = 10 m s^{- 2})$

$0.5 m s^{- 2}$

$1.5 m s^{- 2}$

$2.5 m s^{- 2}$

$3.5 m s^{- 2}$