Two blocks A and B are arranged as shown in the figure. The pulley is frictionless. The mass of A is 10 kg. The coefficient of friction of A with the horizontal surface is 0.20. To stan the motion the minimum mass of B is

Question

Two blocks A and B are arranged as shown in the figure. The pulley is frictionless. The mass of A is 10 kg. The coefficient of friction of A with the horizontal surface is 0.20. To stan the motion the minimum mass of B is (A) 2 kg (B) 0.2 kg (C) 5 kg (D) 10 kg

Tardigrade Admin · Accepted Answer

Mass of block μ F Coefficient of friction μ F Force of friction μ F where R is reaction of plane. ie, μ F μ F [ML-1T-2] To start motion force due to B must be equal to F. ie, [MLT-1] [MLT-2] [ML2T-2] (3aT/2)

Q. Two blocks A and B are arranged as shown in the figure. The pulley is frictionless. The mass of A is 10 kg. The coefficient of friction of A with the horizontal surface is 0.20. To stan the motion the minimum mass of B is

2 kg

0.2 kg

5 kg

10 kg

Mass of block $μ F$ Coefficient of friction $μ F$ Force of friction $μ F$ where R is reaction of plane. ie, $μ F$ $μ F$ $[M L^{- 1} T^{- 2}]$ To start motion force due to B must be equal to F. ie, $[M L T^{- 1}]$ $[M L T^{- 2}]$ $[M L^{2} T^{- 2}]$ $\frac{3 a T}{2}$

Q. Two blocks A and B are arranged as shown in the figure. The pulley is frictionless. The mass of A is 10 kg. The coefficient of friction of A with the horizontal surface is 0.20. To stan the motion the minimum mass of B is

2 kg

0.2 kg

5 kg

10 kg

Mass of block μF Coefficient of friction μF Force of friction μF where R is reaction of plane. ie, μF μF [ML−1T−2] To start motion force due to B must be equal to F. ie, [MLT−1] [MLT−2] [ML2T−2] 23aT​

Mass of block $μ F$ Coefficient of friction $μ F$ Force of friction $μ F$ where R is reaction of plane. ie, $μ F$ $μ F$ $[M L^{- 1} T^{- 2}]$ To start motion force due to B must be equal to F. ie, $[M L T^{- 1}]$ $[M L T^{- 2}]$ $[M L^{2} T^{- 2}]$ $\frac{3 a T}{2}$