Two balls A and B are thrown simultaneously from the top of a tower. A is thrown vertically up with a speed of 4 ms -1 . B is thrown vertically down with a speed of 4 ms -1. The ball A and B hit the ground with speed vA and vB respectively. Then,

Question

Two balls A and B are thrown simultaneously from the top of a tower. A is thrown vertically up with a speed of 4 ms -1 . B is thrown vertically down with a speed of 4 ms -1. The ball A and B hit the ground with speed vA and vB respectively. Then, (A) vA < vB (B) vA > vB (C) vA ≥ vB (D) vA = vB

Tardigrade Admin · Accepted Answer

When A retums to the level of top of tower, its downward velocity is 4 ms -1. This velocity is the same as that of B. So, both A and B hit the ground with the same velocity.

Q. Two balls $A$ and $B$ are thrown simultaneously from the top of a tower. $A$ is thrown vertically up with a speed of $4 m s^{- 1} . B$ is thrown vertically down with a speed of $4 m s^{- 1}$ . The ball $A$ and $B$ hit the ground with speed $v_{A}$ and $v_{B}$ respectively. Then,

$v_{A} < v_{B}$

$v_{A} > v_{B}$

$v_{A} \geq v_{B}$

$v_{A} = v_{B}$

When $A$ retums to the level of top of tower, its downward velocity is $4 m s^{- 1}$ . This velocity is the same as that of $B$ . So, both $A$ and $B$ hit the ground with the same velocity.

Q. Two balls A and B are thrown simultaneously from the top of a tower. A is thrown vertically up with a speed of 4ms−1.B is thrown vertically down with a speed of 4ms−1. The ball A and B hit the ground with speed vA​ and vB​ respectively. Then,

vA​<vB​

vA​>vB​

vA​≥vB​

vA​=vB​