Total number of canines in permanent dental set of humans are

Question

Total number of canines in permanent dental set of humans are (A) 6 (B) 4 (C) 8 (D) 12

Tardigrade Admin · Accepted Answer

The dental formula of human is 2 ×((2123/2123)). The sequence of teeth are incisor, canine, premolar and molar. Therefore, the total number of canine in upper and lower (complete dentine set) jaw is 4 .

Q. Total number of canines in permanent dental set of humans are

6

4

8

12

The dental formula of human is $2 \times (\frac{2123}{2123})$ .
The sequence of teeth are incisor, canine, premolar and molar. Therefore, the total number of canine in upper and lower (complete dentine set) jaw is $4$ .

Q. Total number of canines in permanent dental set of humans are

6

4

8

12

The dental formula of human is 2×(21232123​). The sequence of teeth are incisor, canine, premolar and molar. Therefore, the total number of canine in upper and lower (complete dentine set) jaw is 4 .

The dental formula of human is $2 \times (\frac{2123}{2123})$ .
The sequence of teeth are incisor, canine, premolar and molar. Therefore, the total number of canine in upper and lower (complete dentine set) jaw is $4$ .