Question

Total number of atoms in $44g$ of $C{O}_2$ is

• A. $6.02\times 10^{23}$
• B. $6.02\times 10^{24}$
• C. $1.806\times 10^{24}$
• D. $18.06\times 10^{22}$

Answer 1

Answer: (C)

$44g$ of $C{O}_2=6.023\times 10^{23}$ molecules of $C{O}_2=3\times 6.023\times 10^{23}$ atoms $=1.806\times 10^{24}$ atoms