To establish an instantaneous displacement current of I ampere in the space between the plates of a parallel plate capacitor of (1/2) farad, the value of (d V/d t) is

Question

To establish an instantaneous displacement current of I ampere in the space between the plates of a parallel plate capacitor of (1/2) farad, the value of (d V/d t) is (A) 2 I (B) (I/2) (C) (1/2I) (D) I

Tardigrade Admin · Accepted Answer

Id=(A ε0/d) (d E/d t) × d I=(1/2) (d E/d t) × d I=(1/2) (d V/d t) × (1/d) ⋅ d (d V/d t)=2 I

Q. To establish an instantaneous displacement current of $I$ ampere in the space between the plates of a parallel plate capacitor of $\frac{1}{2}$ farad, the value of $\frac{d V}{d t}$ is

$2 I$

$\frac{I}{2}$

$\frac{1}{2 I}$

$I$

$I_{d} = \frac{A ε _{0}}{d} \frac{d E}{d t} \times d$
$I = \frac{1}{2} \frac{d E}{d t} \times d$
$I = \frac{1}{2} \frac{d V}{d t} \times \frac{1}{d} \cdot d$
$\frac{d V}{d t} = 2 I$

Q. To establish an instantaneous displacement current of I ampere in the space between the plates of a parallel plate capacitor of 21​ farad, the value of dtdV​ is

2I

2I​

2I1​

I

Id​=dAε0​​dtdE​×d I=21​dtdE​×d I=21​dtdV​×d1​⋅d dtdV​=2I

Q. To establish an instantaneous displacement current of $I$ ampere in the space between the plates of a parallel plate capacitor of $\frac{1}{2}$ farad, the value of $\frac{d V}{d t}$ is

$2 I$

$\frac{I}{2}$

$\frac{1}{2 I}$

$I$

$I_{d} = \frac{A ε _{0}}{d} \frac{d E}{d t} \times d$
$I = \frac{1}{2} \frac{d E}{d t} \times d$
$I = \frac{1}{2} \frac{d V}{d t} \times \frac{1}{d} \cdot d$
$\frac{d V}{d t} = 2 I$