To double the translational kinetic energy of the molecules of a gas one has to

Question

To double the translational kinetic energy of the molecules of a gas one has to (A) double the absolute temperature (B) reduce the absolute temperature to half (C) increase the absolute temperature fourfold (D) increase the absolute temperature by a factor of √2

Tardigrade Admin · Accepted Answer

: The mean kinetic energy of translation =(3R/2)T EK propto T Hence to double EK, absolute temperature T be double.

Q. To double the translational kinetic energy of the molecules of a gas one has to

double the absolute temperature

reduce the absolute temperature to half

increase the absolute temperature fourfold

increase the absolute temperature by a factor of $2$

: The mean kinetic energy of translation $= \frac{3 R}{2} T$ $E_{K} \propto T$ Hence to double $E_{K},$ absolute temperature T be double.