To balance the following reaction, 2 Mn 2++A S 2 O 82-+B H 2 O longrightarrow 2 MnO 4-+C SO 42-+D H + stoichiometric coefficients A, B, C and D have been used. What would be the exact value of these coefficients?

Question

To balance the following reaction, 2 Mn 2++A S 2 O 82-+B H 2 O longrightarrow 2 MnO 4-+C SO 42-+D H + stoichiometric coefficients A, B, C and D have been used. What would be the exact value of these coefficients? (A) A-3 B-4 C-5 D-8  (B)  A-5 B-8 C-10 D-16  (C) A-10 B-16 C-20 D-32  (D) A-8 B-5 C-32 D-20

Tardigrade Admin · Accepted Answer

2 Mn 2++5 S 2 O 82-+8 H 2 O longrightarrow 2 MnO 4-+10 SO 42-+16 H +

Q. To balance the following reaction,
$2 M n^{2 +} + A S_{2} O_{8}^{2 -} + B H_{2} O ⟶ 2 M n O_{4}^{-} + CS O_{4}^{2 -} + D H^{+}$
stoichiometric coefficients $A, B, C$ and $D$ have been used. What would be the exact value of these coefficients?

$A - 3 B - 4 C - 5 D - 8$

$A - 5 B - 8 C - 10 D - 16$

$A - 10 B - 16 C - 20 D - 32$

$A - 8 B - 5 C - 32 D - 20$

$2 M n^{2 +} + 5 S_{2} O_{8}^{2 -} + 8 H_{2} O ⟶ 2 M n O_{4}^{-} + 10 S O_{4}^{2 -} + 16 H^{+}$

Q. To balance the following reaction, 2Mn2++AS2​O82−​+BH2​O⟶2MnO4−​+CSO42−​+DH+ stoichiometric coefficients A,B,C and D have been used. What would be the exact value of these coefficients?

A−3B−4C−5D−8

A−5B−8C−10D−16

A−10B−16C−20D−32

A−8B−5C−32D−20