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Tardigrade
Question
Physics
Three resistances of values 2Ω, 3Ω and 6Ω are to be connected to produce an effective resistance of 4Ω . This can be done by connecting
Q. Three resistances of values 2
Ω
, 3
Ω
and 6
Ω
are to be connected to produce an effective resistance of 4
Ω
. This can be done by connecting
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A
6
Ω
resistance in series with the parallel combination of 2
Ω
and 3
Ω
0%
B
3
Ω
resistance in series with the parallel combination of 2
Ω
and 6
Ω
0%
C
2
Ω
resistance in series with the parallel combination of 3
Ω
and 6
Ω
100%
D
2
Ω
resistance in parallel with the parallel combination of 3
Ω
and 6
Ω
0%
Solution:
Parallel combination of 3
Ω
and 6
Ω
gives effective resistance,
R
p
=
3
+
6
3
X
6
=
9
18
=
2Ω
This in series with
2
Ω
gives net ressistance as 4
Ω