Question

Three resistances each of $4\Omega$ are connected to form a triangle. The resistance between any two terminals is

• A. $12\Omega$
• B. $2\Omega$
• C. $6\Omega$
• D. $8/3\Omega$

Answer 1

Answer: (D)

The two resistances are connected in series and the resultant is connected in parallel with the third resistance.
$\therefore R=4\Omega +4\Omega =8\Omega$
and $\frac{1}{R^{\prime \prime }}=\frac{1}{8}+\frac{1}{4}=\frac{3}{8}$
or $R^{\prime \prime }=\frac{8}{3}\Omega$