Q.
Three particles of masses 1kg,23kg, and 2kg are located at the vertices of an equilateral triangle of side a. The x,y coordinates of the centre of mass are
10717
227
System of Particles and Rotational Motion
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Solution:
Let the masses 1kg,23kg and 2kg are located at the vertices A,B and C as shown in figure. The coordinates of points A,B and C are(0,0),(a,0),2a,23a respectively.
The coordinates of centre of mass are XCM=m1+m2+m3m1x1+m2x2+m3x3 =[1+23+2][1×0+23×a+2×2a]=95a YCM=m1+m2+m3m1y1+m2y2+m3y3 =[1+23+2][1×0+23×0+2×23a] =923a =332a