Three particles, each having a charge of 10 μ C are placed at the corners of an equilateral triangle of side 10 cm . The electrostatic potential energy of the system is ( textGiven (1/4πε0) = 9 ×109 N-m2 C2)

Question

Three particles, each having a charge of 10 μ C are placed at the corners of an equilateral triangle of side 10 cm . The electrostatic potential energy of the system is ( textGiven (1/4πε0) = 9 ×109 N-m2 C2)  (A) Zero (B)  ∞  (C)  27 J  (D)  100 J

Tardigrade Admin · Accepted Answer

For a pair of charges U=(1/4 π ε0) (q1 q2/r) U text system =(1/4 π ε0)[(10 × 10-6 × 10 × 10-6/10 / 100). +(10 × 10-6 × 10 × 10-6/10 / 100) + .(10 × 10-6 × 10 × 10-6/10 / 100)] =3 × 9 × 109 × (100 × 10-12 × 100/10) =27 J

Q. Three particles, each having a charge of $10 μ C$ are placed at the corners of an equilateral triangle of side $10 c m$ . The electrostatic potential energy of the system is
$(Given \frac{1}{4 π ε _{0}} = 9 \times 1 0^{9} N - m^{2} C^{2})$

Zero

$\infty$

$27 J$

$100 J$

Q. Three particles, each having a charge of 10μC are placed at the corners of an equilateral triangle of side 10cm . The electrostatic potential energy of the system is (Given4πε0​1​=9×109N−m2C2)

Zero

∞

27J

100J

For a pair of charges U=4πε0​1​rq1​q2​​ Usystem ​=4πε0​1​[10/10010×10−6×10×10−6​ +10/10010×10−6×10×10−6​ +10/10010×10−6×10×10−6​] =3×9×109×10100×10−12×100​ =27J

Q. Three particles, each having a charge of $10 μ C$ are placed at the corners of an equilateral triangle of side $10 c m$ . The electrostatic potential energy of the system is
$(Given \frac{1}{4 π ε _{0}} = 9 \times 1 0^{9} N - m^{2} C^{2})$

$\infty$

$27 J$

$100 J$