Q.
Three parallel straight lines L1,L2 and L3 lie on the the same plane. Consider 5 points on L1,7 points on L2 and 9 points on L3. Then the maximum possible number of triangles formed with vertices at these points, is
Number of triangles if one vertex at each line is =5C1×7C1×9C1=315
Number of triangles if two vertices at L1 and remaining at either L2 or L3 is =5C2×16C1=160
Number of triangles if two vertices at L2 and remaining at either L3 or L1 is =7C2×14C1=294
and number of triangles if two vertices at L3 and remaining at either L1 or L2 is: 9C2×12C1=432
So, total maximum possible number of triangles =1201