Three non-conducting large parallel plates have surface charge densities σ ,-2σ and 4σ respectively as shown in the figure. The electric field at the point P is

Question

Three non-conducting large parallel plates have surface charge densities σ ,-2σ and 4σ respectively as shown in the figure. The electric field at the point P is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-8w7at7f0fnj2qwhj.jpg" /> (A) (σ /ϵ 0) (B) (σ /2 ϵ 0) (C) (3 σ /2 ϵ 0) (D) (3 σ /ϵ 0)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-8w7at7f0fnj27roq.jpg" /> The electric charge densities are σ , -2σ and 4σ respectively. Hence, electric field at point P is given by EP=(σ /2 ϵ 0)+(- 2 σ /2 ϵ 0)+(4 σ /2 ϵ 0) =(σ - 2 σ + 4 σ /2 ϵ 0) =(3 σ /2 ϵ 0)

Q. Three non-conducting large parallel plates have surface charge densities $σ, - 2 σ$ and $4 σ$ respectively as shown in the figure. The electric field at the point $P$ is

$\frac{σ}{ϵ _{0}}$

$\frac{σ}{2 ϵ _{0}}$

$\frac{3 σ}{2 ϵ _{0}}$

$\frac{3 σ}{ϵ _{0}}$

The electric charge densities are $σ, - 2 σ$ and $4 σ$ respectively.
Hence, electric field at point $P$ is given by
$E_{P} = \frac{σ}{2 ϵ _{0}} + \frac{- 2 σ}{2 ϵ _{0}} + \frac{4 σ}{2 ϵ _{0}}$
$= \frac{σ - 2 σ + 4 σ}{2 ϵ _{0}}$
$= \frac{3 σ}{2 ϵ _{0}}$

Q. Three non-conducting large parallel plates have surface charge densities σ,−2σ and 4σ respectively as shown in the figure. The electric field at the point P is

ϵ0​σ​

2ϵ0​σ​

2ϵ0​3σ​

ϵ0​3σ​