Three electric bulbs of 200 W, 200 W and 400 W are shown in figure. The resultant power of the combination is

Question

Three electric bulbs of 200 W, 200 W and 400 W are shown in figure. The resultant power of the combination is (A) 800 W (B) 400 W (C) 200 W (D) 600 W

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/fc3ac3118c474b6974e4ccac30360883-.png" /> Bulbs A and B are in parallel, their effective power is P'=PA+PB=200 W +200 W =400 W P' and bulb C are in series, the resultant power of the combination is PR=(P' × PC/P'+PC)=(400 W × 400 W /400 W +400 W )=200 W

Q. Three electric bulbs of $200 W, 200 W$ and $400 W$ are shown in figure. The resultant power of the combination is

800 W

400 W

200 W

600 W

Bulbs $A$ and $B$ are in parallel, their effective power is
$P^{'} = P_{A} + P_{B} = 200 W + 200 W = 400 W$
$P^{'}$ and bulb $C$ are in series, the resultant power of the combination is
$P_{R} = \frac{P ^{'} \times P _{C}}{P ^{'} + P _{C}} = \frac{400 W \times 400 W}{400 W + 400 W} = 200 W$

Q. Three electric bulbs of 200W,200W and 400W are shown in figure. The resultant power of the combination is