Three containers of the same volume contain three different gases. The masses of the molecules are m1, m2 and m3 and the number of molecules in their respective containers are N1, N2 and N3. The gas pressure in the containers are P1, P2 and P3 respectively. All the gases are now mixed and put in one of these containers. The pressure P of the mixture will be

Question

Three containers of the same volume contain three different gases. The masses of the molecules are m1, m2 and m3 and the number of molecules in their respective containers are N1, N2 and N3. The gas pressure in the containers are P1, P2 and P3 respectively. All the gases are now mixed and put in one of these containers. The pressure P of the mixture will be (A) P < (P1 + P2 + P3) (B) P = (P1 + P2 + P3/3) (C)  P = P1 + P2 + P3 (D)  P > (P1 + P2 + P3)

Tardigrade Admin · Accepted Answer

According to Dalton’s law of partial pressures, we have P = P1 + P2 + P3

$P < (P_{1} + P_{2} + P_{3})$

$P = \frac{P _{1} + P _{2} + P _{3}}{3}$

$P = P_{1} + P_{2} + P_{3}$

$P > (P_{1} + P_{2} + P_{3})$

According to Dalton’s law of partial pressures, we have $P = P_{1} + P_{2} + P_{3}$

P<(P1​+P2​+P3​)

P=3P1​+P2​+P3​​

P=P1​+P2​+P3​

P>(P1​+P2​+P3​)

According to Dalton’s law of partial pressures, we have P=P1​+P2​+P3​

$P < (P_{1} + P_{2} + P_{3})$

$P = \frac{P _{1} + P _{2} + P _{3}}{3}$

$P = P_{1} + P_{2} + P_{3}$

$P > (P_{1} + P_{2} + P_{3})$

According to Dalton’s law of partial pressures, we have $P = P_{1} + P_{2} + P_{3}$