Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also name the triangle formed by the forces as sides

Question

Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also name the triangle formed by the forces as sides (A) 60° equilateral triangle (B) 120° equilateral triangle (C) 120°, 30°, 30° an isosceles triangle (D) 120° an obtuse angled triangle

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/c25c4520282bec792cc2b11cd72d6bff-.png" /> In N forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given θ=(360/N)=(360/3)=120°

Q. Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also name the triangle formed by the forces as sides

$6 0^{\circ}$ equilateral triangle

$12 0^{\circ}$ equilateral triangle

$12 0^{\circ}, 3 0^{\circ}, 3 0^{\circ}$ an isosceles triangle

$12 0^{\circ}$ an obtuse angled triangle

In $N$ forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given
$θ = \frac{360}{N} = \frac{360}{3} = 12 0^{\circ}$

Q. Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also name the triangle formed by the forces as sides

60∘ equilateral triangle

120∘ equilateral triangle

120∘,30∘,30∘ an isosceles triangle

120∘ an obtuse angled triangle

In N forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given θ=N360​=3360​=120∘

$6 0^{\circ}$ equilateral triangle

$12 0^{\circ}$ equilateral triangle

$12 0^{\circ}, 3 0^{\circ}, 3 0^{\circ}$ an isosceles triangle

$12 0^{\circ}$ an obtuse angled triangle

In $N$ forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given
$θ = \frac{360}{N} = \frac{360}{3} = 12 0^{\circ}$