Three blocks of masses m1, m2 and m3 are connected by massless strings as shown on a frictionless table. They are pulled with a force of 40 N. If m1=10 kg , m2=6 kg and m3=4 kg, then tension T2 will be

Question

Three blocks of masses m1, m2 and m3 are connected by massless strings as shown on a frictionless table. They are pulled with a force of 40 N. If m1=10 kg , m2=6 kg and m3=4 kg, then tension T2 will be (A) 10 N (B) 20 N (C) 32 N (D) 40 N

Tardigrade Admin · Accepted Answer

From Newton's law, the force (F) is given by F=M a where a is acceleration and M the mass. Given, M =m1+m2+m3 =10+6+4=20 kg , F =40 N ∴ a =(F/M)=(40/20)=2 m / s 2 Tension between 10 kg and 6 kg masses is given by T2 =(m2+m3) a =(6+4) 2 =10 × 2=20 N

Q. Three blocks of masses m1​,m2​ and m3​ are connected by massless strings as shown on a frictionless table. They are pulled with a force of 40N. If m1​=10kg,m2​=6kg and m3​=4kg, then tension T2​ will be

10 N

20 N

32 N

40 N

From Newton's law, the force (F) is given by F=Ma where a is acceleration and M the mass. Given, M=m1​+m2​+m3​ =10+6+4=20kg, F=40N ∴a=MF​=2040​=2m/s2 Tension between 10kg and 6kg masses is given by T2​=(m2​+m3​)a =(6+4)2 =10×2=20N

Q. Three blocks of masses $m_{1}, m_{2}$ and $m_{3}$ are connected by massless strings as shown on a frictionless table. They are pulled with a force of $40 N$ . If $m_{1} = 10 k g, m_{2} = 6 k g$ and $m_{3} = 4 k g$ , then tension $T_{2}$ will be