Three blocks are connected, as shown in the figure. Calculate the minimum force required to move the blocks with constant velocity. The co-efficient of friction at all surfaces is 0.25 . [Assume that rod does not exerts force in vertical direction]

Question

Three blocks are connected, as shown in the figure. Calculate the minimum force required to move the blocks with constant velocity. The co-efficient of friction at all surfaces is 0.25 . [Assume that rod does not exerts force in vertical direction] <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-hgmuu9acuuqx.png" /> (A) 12m g / 4 (B) 13m g / 4 (C) 3 mg (D) None

Tardigrade Admin · Accepted Answer

F-(3 m g/4)-(6 m g/4)-T=0 ....(i) Solution

T-(m g/4)-(3 m g/4)=0 ....(ii) From equarions (i) and (ii) ⇒ F=13(m g/4)

Q. Three blocks are connected, as shown in the figure. Calculate the minimum force required to move the blocks with constant velocity. The co-efficient of friction at all surfaces is $0.25$ .

[Assume that rod does not exerts force in vertical direction]

$12 m g /4$

$13 m g /4$

$3 m g$

None

$F - \frac{3 m g}{4} - \frac{6 m g}{4} - T = 0$ ....(i)

$T - \frac{m g}{4} - \frac{3 m g}{4} = 0$ ....(ii)
From equarions (i) and (ii)
$\Rightarrow F = 13 \frac{m g}{4}$

Q. Three blocks are connected, as shown in the figure. Calculate the minimum force required to move the blocks with constant velocity. The co-efficient of friction at all surfaces is 0.25 . [Assume that rod does not exerts force in vertical direction]

12mg/4

13mg/4

3mg