Question

Thomson determined the value of $e/m_e$ as

• A. $1.758820\times 10^{10}Ck{g}^{-1}$
• B. $17.58820\times 10^{12}Ck{g}^{-1}$
• C. $1.758820\times 10^{9}Ck{g}^{-1}$
• D. $1.758820\times 10^{11}Ck{g}^{-1}$

Answer 1

Answer: (D)

Thomson was able to determine the charge to the mass ratio of electron by carrying out accurate measurements on the amount of deflections observed by the electrons on the electric field strength or magnetic field strength as,
$e/m_e=1.758820\times 10^{11}Ck{g}^{-1}$
where, $m_e$ is the mass of electron in $kg$ and $e$ is the magnitude of the charge on the electron in Coulomb $(C)$.