There is a uniform electrostatic field in a region. The potential at various points on a small sphere centred at P, in the region, is found to vary between the limits 589.0 V to 589.8 V. What is the potential at a point on the sphere whose radius vector makes an angle of 60° with the direction of the field ?

Question

There is a uniform electrostatic field in a region. The potential at various points on a small sphere centred at P, in the region, is found to vary between the limits 589.0 V to 589.8 V. What is the potential at a point on the sphere whose radius vector makes an angle of 60° with the direction of the field ? (A) 589.5 V (B) 589.2 V (C) 589.4 V (D) 589.6 V

Tardigrade Admin · Accepted Answer

Δ V = E.d 0.8 = Ed (max) Δ V = Edcosθ = 0.8 × cos 60 = 0.4 589.4

589.5 V

589.2 V

589.4 V

589.6 V

ΔV=E.d 0.8=Ed(max) ΔV=Edcosθ=0.8×cos60 =0.4<br/>589.4

$Δ V = E . d$
$0.8 = E d (ma x)$
$Δ V = E d cos θ = 0.8 \times cos 60$
$= 0.4 < b r / > 589.4$