There are two hollow spherical conductors A and B are given below. Points M and N can be connected by conductor wire. Initially (before the connection of points M and N) conductor B is neutral, while charge appeared on conductor A is q. After connecting the spheres, the potential of sphere B is

Question

There are two hollow spherical conductors A and B are given below. Points M and N can be connected by conductor wire. Initially (before the connection of points M and N) conductor B is neutral, while charge appeared on conductor A is q. After connecting the spheres, the potential of sphere B is (A)  (q/4π ε 0(r+R))  (B)  (q/4π ε 0R)  (C)  (q/4π ε 0(r+R))  (D) Zero

Tardigrade Admin · Accepted Answer

After connection, the total charge on inner conductor transfers to outer one and in this situation potential of sphere B is given as VB=(q/4π ε 0R) Because both the spheres will attain an equal potential.

Q. There are two hollow spherical conductors A and B are given below. Points M and N can be connected by conductor wire.
Initially (before the connection of points M and N) conductor B is neutral, while charge appeared on conductor A is q. After connecting the spheres, the potential of sphere B is

$\frac{q}{4 π ε _{0} ( r + R )}$

$\frac{q}{4 π ε _{0} R}$

$\frac{q}{4 π ε _{0} ( r + R )}$

Zero

After connection, the total charge on inner conductor transfers to outer one and in this situation potential of sphere B is given as $V_{B} = \frac{q}{4 π ε _{0} R}$ Because both the spheres will attain an equal potential.

Q. There are two hollow spherical conductors A and B are given below. Points M and N can be connected by conductor wire. Initially (before the connection of points M and N) conductor B is neutral, while charge appeared on conductor A is q. After connecting the spheres, the potential of sphere B is

4πε0​(r+R)q​

4πε0​Rq​

4πε0​(r+R)q​

Zero

After connection, the total charge on inner conductor transfers to outer one and in this situation potential of sphere B is given as VB​=4πε0​Rq​ Because both the spheres will attain an equal potential.

Q. There are two hollow spherical conductors A and B are given below. Points M and N can be connected by conductor wire.
Initially (before the connection of points M and N) conductor B is neutral, while charge appeared on conductor A is q. After connecting the spheres, the potential of sphere B is

$\frac{q}{4 π ε _{0} ( r + R )}$

$\frac{q}{4 π ε _{0} R}$

$\frac{q}{4 π ε _{0} ( r + R )}$

After connection, the total charge on inner conductor transfers to outer one and in this situation potential of sphere B is given as $V_{B} = \frac{q}{4 π ε _{0} R}$ Because both the spheres will attain an equal potential.