There are N coplanar vectors each of magnitude V. Each vector is inclined to the preceding vector at angle (2 π/N) . What is the magnitude of their resultant?

Question

There are N coplanar vectors each of magnitude V. Each vector is inclined to the preceding vector at angle (2 π/N) . What is the magnitude of their resultant? (A) (V/N) (B) V (C) Zero (D) (N/V)

Tardigrade Admin · Accepted Answer

Since each of N-coplanar vector is inclined at (2 π/N) to the preceding hence, they will form a closed polygon. Therefore, their resultant must be zero.

Q. There are N coplanar vectors each of magnitude V. Each vector is inclined to the preceding vector at angle $\frac{2 π}{N} .$
What is the magnitude of their resultant?

$\frac{V}{N}$

V

Zero

$\frac{N}{V}$

Since each of N-coplanar vector is inclined at $\frac{2 π}{N}$ to the preceding hence, they will form a closed polygon. Therefore, their resultant must be zero.

Q. There are N coplanar vectors each of magnitude V. Each vector is inclined to the preceding vector at angle N2π​. What is the magnitude of their resultant?

NV​

V

Zero

VN​

Since each of N-coplanar vector is inclined at N2π​ to the preceding hence, they will form a closed polygon. Therefore, their resultant must be zero.

Q. There are N coplanar vectors each of magnitude V. Each vector is inclined to the preceding vector at angle $\frac{2 π}{N} .$
What is the magnitude of their resultant?

$\frac{V}{N}$

$\frac{N}{V}$

Since each of N-coplanar vector is inclined at $\frac{2 π}{N}$ to the preceding hence, they will form a closed polygon. Therefore, their resultant must be zero.