The work functions of Silver and Sodium are 4.6 and 2.3 eV, respectively. The ratio of the slope of the stopping potential versus frequency plot for Silver to that of Sodium is

Question

The work functions of Silver and Sodium are 4.6 and 2.3 eV, respectively. The ratio of the slope of the stopping potential versus frequency plot for Silver to that of Sodium is (A) 1 (B) 2 (C) 4 (D) zero

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5c6eaa60da526bb201233dfc830364f3-.png" /> For photoelectric effect (h v/e)-(φ0/e)=Vo The slope is tan θ=( h / e )= constant ∴ The ratio will be 1 .

Q. The work functions of Silver and Sodium are $4.6$ and $2.3 e V$ , respectively. The ratio of the slope of the stopping potential versus frequency plot for Silver to that of Sodium is

1

2

4

zero

For photoelectric effect
$\frac{h v}{e} - \frac{ϕ _{0}}{e} = V_{o}$
The slope is $tan θ = \frac{h}{e} =$ constant
$∴$ The ratio will be 1 .

Q. The work functions of Silver and Sodium are 4.6 and 2.3eV, respectively. The ratio of the slope of the stopping potential versus frequency plot for Silver to that of Sodium is

1

2

4

zero

For photoelectric effect ehv​−eϕ0​​=Vo​ The slope is tanθ=eh​= constant ∴ The ratio will be 1 .

Q. The work functions of Silver and Sodium are $4.6$ and $2.3 e V$ , respectively. The ratio of the slope of the stopping potential versus frequency plot for Silver to that of Sodium is

For photoelectric effect
$\frac{h v}{e} - \frac{ϕ _{0}}{e} = V_{o}$
The slope is $tan θ = \frac{h}{e} =$ constant
$∴$ The ratio will be 1 .