The work function of a metal is 5 eV. What is the kinetic energy of the photoelectron ejected from the metal surface if the energy of the incident radiation is 6.2 eV ? (1 eV = 1.6 × 10-19 J)

Question

The work function of a metal is 5 eV. What is the kinetic energy of the photoelectron ejected from the metal surface if the energy of the incident radiation is 6.2 eV ? (1 eV = 1.6 × 10-19 J) (A) 6.626 × 10-19 J (B) 8.01 × 10-19 J (C) 1.92 × 10-18 J (D) 8.010 × 10-18 J

Tardigrade Admin · Accepted Answer

Work function (W)=h v0=5 eV Energy of incident radiation, h v=6.2 eV Kinetic energy of photoelectron =h v-W =6.2-5 =1.2 eV =1.2 × 1.6 × 10-19 J =1.92 × 10-19 J

Q. The work function of a metal is $5 e V$ . What is the kinetic energy of the photoelectron ejected from the metal surface if the energy of the incident radiation is $6.2 e V$ ?
( $1 e V = 1.6 \times 1 0^{- 19} J$ )

$6.626 \times 1 0^{- 19} J$

$8.01 \times 1 0^{- 19} J$

$1.92 \times 1 0^{- 18} J$

$8.010 \times 1 0^{- 18} J$

$1.92 \times 1 0^{- 19} J$

Work function $(W) = h v_{0} = 5 e V$

Energy of incident radiation,

$h v = 6.2 e V$

Kinetic energy of photoelectron

$= h v - W$

$= 6.2 - 5$

$= 1.2 e V$

$= 1.2 \times 1.6 \times 1 0^{- 19} J$

$= 1.92 \times 1 0^{- 19} J$

Q. The work function of a metal is 5eV. What is the kinetic energy of the photoelectron ejected from the metal surface if the energy of the incident radiation is 6.2eV ? (1eV=1.6×10−19J)

6.626×10−19J

8.01×10−19J

1.92×10−18J

8.010×10−18J

1.92×10−19J

Work function (W)=hv0​=5eV Energy of incident radiation, hv=6.2eV Kinetic energy of photoelectron =hv−W =6.2−5 =1.2eV =1.2×1.6×10−19J =1.92×10−19J