The weight of iron which will be converted into its oxide ( Fe 3 O 4) by the action of 18 g of steam on it will be (At. wt. of Fe =56 )

Question

The weight of iron which will be converted into its oxide ( Fe 3 O 4) by the action of 18 g of steam on it will be (At. wt. of Fe =56 ) (A) 168 g (B) 84 g (C) 42 g (D) 21 g

Tardigrade Admin · Accepted Answer

underset3 × 56 g3 Fe + underset4 × 18 g4 H 2 O longrightarrow Fe 3 O 4+4 H 2 4 × 18 g H 2 O ≡ 3 × 56 g Fe ∴ 18 g H 2 O ≡ (3 × 56/4) ≡ 42 g

Q. The weight of iron which will be converted into its oxide $(F e_{3} O_{4})$ by the action of $18 g$ of steam on it will be (At. wt. of $F e = 56$ )

168 g

84 g

42 g

21 g

$3 \times 56 g 3 F e + 4 \times 18 g 4 H_{2} O ⟶ F e_{3} O_{4} + 4 H_{2}$
$4 \times 18 g H_{2} O \equiv 3 \times 56 g F e$
$∴ 18 g H_{2} O \equiv \frac{3 \times 56}{4}$
$\equiv 42 g$

Q. The weight of iron which will be converted into its oxide (Fe3​O4​) by the action of 18g of steam on it will be (At. wt. of Fe=56 )