The volume-temperature graphs of a given mass of an ideal gas at constant pressures are shown below. What is the correct order of pressures?

Question

The volume-temperature graphs of a given mass of an ideal gas at constant pressures are shown below. What is the correct order of pressures? <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-o7avz01vyhbwfciy.jpg" /> (A) p1>p3>p2 (B) p1>p2>p3 (C) p2>p3>p1 (D) p2>p1>p3

Tardigrade Admin · Accepted Answer

Drawing a constant temperature line parallel to 'V' axis, the isobar at higher volumes will be at lower pressure as textP propto (1/ textV) at constant temperature.

Q. The volume-temperature graphs of a given mass of an ideal gas at constant pressures are shown below. What is the correct order of pressures?

$p_{1} > p_{3} > p_{2}$

$p_{1} > p_{2} > p_{3}$

$p_{2} > p_{3} > p_{1}$

$p_{2} > p_{1} > p_{3}$

Drawing a constant temperature line parallel to 'V' axis, the isobar at higher volumes will be at lower pressure as $P \propto \frac{1}{V}$ at constant temperature.

Q. The volume-temperature graphs of a given mass of an ideal gas at constant pressures are shown below. What is the correct order of pressures?

p1​>p3​>p2​

p1​>p2​>p3​

p2​>p3​>p1​

p2​>p1​>p3​

Drawing a constant temperature line parallel to 'V' axis, the isobar at higher volumes will be at lower pressure as P∝V1​ at constant temperature.

$p_{1} > p_{3} > p_{2}$

$p_{1} > p_{2} > p_{3}$

$p_{2} > p_{3} > p_{1}$

$p_{2} > p_{1} > p_{3}$

Drawing a constant temperature line parallel to 'V' axis, the isobar at higher volumes will be at lower pressure as $P \propto \frac{1}{V}$ at constant temperature.