The volume of a gas expands by 0.25 m 3 at a constant pressure of 103 N m -2. The work done is equal to

Question

The volume of a gas expands by 0.25 m 3 at a constant pressure of 103 N m -2. The work done is equal to (A) 2.5 erg (B) 250 J (C) 250 watt (D) 250 newton

Tardigrade Admin · Accepted Answer

We know, work done, w =- P ex +Δ V Given, pressure is 103 N m -2 and, Δ V =0.25 m 3 ∴ w=-103 Nm -2 × 0.25 m 3=-250 J So, work done by the gas is 250 J.

Q. The volume of a gas expands by $0.25 m^{3}$ at a constant pressure of $1 0^{3} N m^{- 2}$ . The work done is equal to

2.5 erg

250 J

250 watt

250 newton

We know, work done, $w = - P_{e x} + Δ V$
Given, pressure is $1 0^{3} N m^{- 2}$
and, $Δ V = 0.25 m^{3}$
$∴ w = - 1 0^{3} N m^{- 2} \times 0.25 m^{3} = - 250 J$
So, work done by the gas is $250 J$ .

Q. The volume of a gas expands by 0.25m3 at a constant pressure of 103Nm−2. The work done is equal to