The volume of 1 mole of any pure gas at

standard and pressure (STP) Is equal to $22.414 L$

$1 L = 1 0^{- 3} m^{3}$

$∴ 22.4 L = 0.022414 m^{3}$

Question

The volume of 1 mole of any pure gas at standard temperature and pressure is always equal to (A)  0.022414 m3 (B)  22.414 m3 (C)  2.2414 m3 (D)  0.22414 m3

Tardigrade Admin · Accepted Answer

The volume of 1 mole of any pure gas at standard and pressure (STP) Is equal to 22.414 L 1 L =10-3 m3 ∴ 22.4 L =0.022414 m3

Q. The volume of $1$ mole of any pure gas at standard temperature and pressure is always equal to

$0.022414 m^{3}$

$22.414 m^{3}$

$2.2414 m^{3}$

$0.22414 m^{3}$

The volume of 1 mole of any pure gas at

standard and pressure (STP) Is equal to $22.414 L$

$1 L = 1 0^{- 3} m^{3}$

$∴ 22.4 L = 0.022414 m^{3}$

Q. The volume of 1 mole of any pure gas at standard temperature and pressure is always equal to

0.022414m3

22.414m3

2.2414m3

0.22414m3

The volume of 1 mole of any pure gas at standard and pressure (STP) Is equal to 22.414L 1L=10−3m3 ∴22.4L=0.022414m3

Q. The volume of $1$ mole of any pure gas at standard temperature and pressure is always equal to

$0.022414 m^{3}$

$22.414 m^{3}$

$2.2414 m^{3}$

$0.22414 m^{3}$

The volume of 1 mole of any pure gas at

standard and pressure (STP) Is equal to $22.414 L$

$1 L = 1 0^{- 3} m^{3}$

$∴ 22.4 L = 0.022414 m^{3}$