The volume, in mL, of 0.02MK2Cr2O7 solution required to react with 0.288g of ferrous oxalate in acidic medium is . (Molar mass of Fe=56gmol- 1 )

Question

The volume, in mL, of 0.02MK2Cr2O7 solution required to react with 0.288g of ferrous oxalate in acidic medium is . (Molar mass of Fe=56gmol- 1 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

K2Cr2O7+FeC2O4 arrow Cr3 ++Fe3 ++CO2 (0 . 02 × vol × 6/1000)=3× (0 . 288/144) Volume=(200/4)=50mL

Q. The volume, in $m L,$ of $0.02 M K_{2} C r_{2} O_{7}$ solution required to react with $0.288 g$ of ferrous oxalate in acidic medium is ________. (Molar mass of $F e = 56 g m o l^{- 1}$ )

$K_{2} C r_{2} O_{7} + F e C_{2} O_{4} \to C r^{3 +} + F e^{3 +} + C O_{2}$
$\frac{0.02 \times v o l \times 6}{1000} = 3 \times \frac{0.288}{144}$
$V o l u m e = \frac{200}{4} = 50 m L$

Q. The volume, in mL, of 0.02MK2​Cr2​O7​ solution required to react with 0.288g of ferrous oxalate in acidic medium is ________. (Molar mass of Fe=56gmol−1 )

K2​Cr2​O7​+FeC2​O4​→Cr3++Fe3++CO2​ 10000.02×vol×6​=3×1440.288​ Volume=4200​=50mL

Q. The volume, in $m L,$ of $0.02 M K_{2} C r_{2} O_{7}$ solution required to react with $0.288 g$ of ferrous oxalate in acidic medium is ________. (Molar mass of $F e = 56 g m o l^{- 1}$ )

$K_{2} C r_{2} O_{7} + F e C_{2} O_{4} \to C r^{3 +} + F e^{3 +} + C O_{2}$
$\frac{0.02 \times v o l \times 6}{1000} = 3 \times \frac{0.288}{144}$
$V o l u m e = \frac{200}{4} = 50 m L$