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Tardigrade
Question
Physics
The vibration of string can be described by the equation y=0.75 cos (2π /5)x sin (60 π s-1)t The speed of wave travelling in the string is
Q. The vibration of string can be described by the equation
y
=
0.75
{
cos
(
2
π
/5
)
x
}
sin
{(
60
π
s
−
1
)
t
}
The speed of wave travelling in the string is
1864
221
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A
24
π
c
m
s
−
1
B
0.3
π
c
m
s
−
1
C
450
c
m
s
−
1
D
150
c
m
s
−
1
Solution:
Given equation
Y
=
(
0.75
)
{
cos
5
2
π
×
sin
(
60
π
)
t
}
Comparing this with standard equation
y
=
a
cos
λ
2
π
x
sin
T
2
π
×
t
We get
5
2
π
=
λ
2
π
⇒
λ
=
5
∵
n
=
30
and
T
2
π
=
60
π
24
π
=
60
π
⇒
V
=
x
λ
=
30
×
5
=
150
c
m
s
−
1