Tardigrade
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Tardigrade
Question
Chemistry
The vapour pressures of ethanol and methanol are 42.0 mm and 88.5 mmHg respectively. An ideal solution is formed at the same temperature by mixing 46.0 g of ethanol with 16.0 g of methanol. The mole fraction of methanol in the vapour is:
Q. The vapour pressures of ethanol and methanol are
42.0
mm
and
88.5
mm
H
g
respectively. An ideal solution is formed at the same temperature by mixing
46.0
g
of ethanol with
16.0
g
of methanol. The mole fraction of methanol in the vapour is:
2418
208
Solutions
Report Error
A
0.467
B
0.502
C
0.513
D
0.556
Solution:
P
m
=
P
M
e
O
H
∘
X
M
e
O
H
∘
+
P
E
roH
∘
X
E
r
O
H
Thus
P
M
=
88.5
×
[
32
16
+
46
46
32
16
]
+
42
×
[
32
16
+
46
46
46
46
]
=
57.5
Now
P
M
e
O
H
′
=
P
M
eoH
o
.
X
M
eoH
(
l
)
=
P
m
×
X
M
e
O
H
(
g
)
∴
88.5
×
[
32
16
+
46
46
32
16
]
=
57.5
X
M
eoH
(
g
)
∴
X
M
e
O
H
=
0.513