The vapour pressure of water at 80° C is 355.5 mm of Hg. A 100 mL vessel contains water saturated with O 2 at 80° C , the total pressure being 760 mm of Hg. The contents of the vessel were pumped into a 50 mL vessel at the same temperature. What is the partial pressure of O 2 ?

Question

The vapour pressure of water at 80° C is 355.5 mm of Hg. A 100 mL vessel contains water saturated with O 2 at 80° C , the total pressure being 760 mm of Hg. The contents of the vessel were pumped into a 50 mL vessel at the same temperature. What is the partial pressure of O 2 ? (A) 1115 mm (B) 809 mm (C) 405 mm (D) 3555 mm

Tardigrade Admin · Accepted Answer

p text Total =p H 2 O +p O 2 p O 2=760-355.5=404.5 mm When the contents were pumped into 50 mL vessel P1=404.5, V1=100 mL , P2=?, V2=50 mL , P1 V1=P2 V2 P2=(404.5 × 100/50)=809 mm Thus, p O 2 in 50 mL vessel =809 mm .

$1115 mm$

$809 mm$

$405 mm$

$3555 mm$

Q. The vapour pressure of water at 80∘C is 355.5mm of Hg. A 100mL vessel contains water saturated with O2​ at 80∘C, the total pressure being 760mm of Hg. The contents of the vessel were pumped into a 50mL vessel at the same temperature. What is the partial pressure of O2​?

1115mm

809mm

405mm

3555mm

pTotal ​=pH2​O​+pO2​​ pO2​​=760−355.5=404.5mm When the contents were pumped into 50mL vessel P1​=404.5,V1​=100mL,P2​=?,V2​=50mL,P1​V1​=P2​V2​ P2​=50404.5×100​=809mm Thus, pO2​​ in 50mL vessel =809mm.

$1115 mm$

$809 mm$

$405 mm$

$3555 mm$