Question

The values of $K_{p_1}$ and $K_{p_2}$ for the reactions
$X\rightleftharpoons Y+Z.......(i)$
and $A\rightleftharpoons 2B.......(ii)$
are in ratio of $9:1$. If degree of dissociation of $X$ and $A$ be equal, then total pressure at equilibrium (i) and (ii) are in the ratio

• A. 3:1
• B. 1:9
• C. 36:1
• D. 1:1

Answer 1

Answer: (C)

$\frac{K_{P_1}}{K_{I_2}}=\frac{\frac{P_1^2{\alpha }^2}{P_1(1+a)}}{\frac{{\left(2P_{2}a\right)}^2}{P_2(1+a)}}\Rightarrow \frac{P_1^2{\alpha }^2\times P_2}{P_1\times 4P_1^2{\alpha }^2{P}_2}$
$\frac{K_{P_1}}{K_{P_2}}=\frac{P_1}{4P_2}=\frac{9}{1}$
$P_1=36P_2$
Total pressure $(1)=P_1+P_1\alpha$
Total pressure $(2)=P_2+P_2\alpha$
$\frac{P_1+P_1\alpha }{P_2+P_2\alpha }=\frac{P_1(1+\alpha )}{P_2(1+\alpha )}\Rightarrow \frac{P_1}{P_2}=36:1$