The value of work done for rotating a magnet of magnetic moment M by an angle θ with respect to magnetic field B is given by :-

Question

The value of work done for rotating a magnet of magnetic moment M by an angle θ with respect to magnetic field B is given by :- (A) MB cos θ (B) 2 MB sin 2 (θ/2) (C) MB sin θ (D) MB(1- sin θ)

Tardigrade Admin · Accepted Answer

W=MB (1- cos θ) = MB 2 sin 2 (θ/2)=2 MB sin 2 (θ/2) =2 MB sin 2 (θ/2)

Q. The value of work done for rotating a magnet of magnetic moment $M$ by an angle $θ$ with respect to magnetic field $B$ is given by :-

$MB cos θ$

$2 MB sin^{2} \frac{θ}{2}$

$MB sin θ$

$MB (1 - sin θ)$

$W = MB (1 - cos θ)$
$= MB 2 sin^{2} \frac{θ}{2} = 2 MB sin^{2} \frac{θ}{2}$
$= 2 MB sin^{2} \frac{θ}{2}$

Q. The value of work done for rotating a magnet of magnetic moment M by an angle θ with respect to magnetic field B is given by :-

MBcosθ

2MBsin22θ​

MBsinθ

MB(1−sinθ)