Question

The value of ${\log }_{\sqrt{2}}\left({\mathrm{antilog}}_{128}\left(\frac{3}{7}\right)\right)$ equals

• A. 16
• B. 8
• C. 6
• D. 4

Answer 1

Answer: (C)

antilog ${\log }_{128}\left(\frac{3}{7}\right)=(128{)}^{\frac{3}{7}}={\left(2^7\right)}^{\frac{3}{7}}=2^3$.
$\therefore {\log }_{\sqrt{2}}(2{)}^3=\frac{3}{1/2}{\log }_{2}2=6$